NCERT Solutions for Class 9 Science Chapter 10 Work and Energy

Author at PW
January 30, 2026
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Work and energy class 9 questions and answers tell us how things move and what makes them go. Work happens when you push or pull an object and it moves some distance. Energy is the power something has to do that work. These pages show you how to find answers for school and learn about moving things easily.

Check Out: Class 9th Books

Class 9 Science Chapter 10 Question Answer

Given below are the NCERT Class 9 Science Chapter 10 Exercise Solutions, explained step by step to help students understand both theory and numerical questions with ease.

1. A force of 7 N acts on an object. The displacement is, say 8 m, in the direction of the force. Let us take it that the force acts on the object through the displacement. What is the work done in this case?

Solution:

When a force F acts on an object to move it in its direction through a distance S,  work is done. The work on the body is done by force. Work done = Force × Displacement W = F × S Where, F = 7 N S = 8 m So, work done, W = 7 × 8 W = 56 Nm W = 56 J

Read More: NCERT Solutions for Class 9 Science Chapter 1

NCERT Solutions Class 9 Science Chapter 10 Exercise 10.2

1. When do we say that work is done?

Solution:

Work is finished as soon as the following requirements are met: (i) The body is subject to a force. (ii) The body is moved by exerting force in the force's direction or the opposite direction.

2. Write an expression for the work done when a force is acting on an object in the direction of its displacement.

Solution:

The work done W on a body when a force F moves it over a distance S in the direction of the applied force is expressed as follows:

3. Define 1 J of work.

Solution:

An object undergoes 1 J of work when a force of 1 N moves it 1 m along the force's line of action.

4. A pair of bullocks exert a force of 140 N on a plow. The field being ploughed is 15 m long.

How much work is done in ploughing the length of the field?

Solution:

Work done by the bullocks is given by the expression: W= F × d Where, Applied force, F = 140 N Displacement, d = 15 m W = 140 x 15 = 2100 J Therefore, 2100 J of work is done in ploughing the length of the field.

Read More: NCERT Solutions for Class 9 Science Chapter 2

NCERT Solutions Class 9 Science Chapter 10 Exercise 10.3

1. What is the kinetic energy of an object?

Solution:

The energy that a body possesses as a result of motion is referred to as kinetic or mechanical energy. Everything in motion has mechanical energy. The body tries to function by using mechanical energy. A nail is driven into a log of wood using the kinetic energy of the hammer, windmills are operated by the mechanical energy of air, etc.

2. Write an expression for the kinetic energy of an object.

Solution:

If a body of mass m is moving with a speed v, then its K.E. E is given by the expression, E = 1/2 m v Its SI unit is Joule (J).

3. The kinetic energy of an object of mass, m moving with a velocity of 5 ms -1 is 25 J. What will be its kinetic energy when its velocity is doubled? What will be its kinetic energy when its velocity is increased three times?

Solution:

Given K.E. of the object = 25J Velocity of the object (v) = 5 m/s K.E. = (½) mv 25 = (½) m (5) 50 = 25 x m m = 50/25 m = 2 kg Now, when velocity is doubled v = 10 m/s m = 2 kg K.E. = (½) x 2 x (10) K.E. = 10 K.E. = 100 J When velocity is increased three times, then v = 15 m/s m = 2 kg K.E. = (½) x 2 x (15) K.E. = (15) K.E. = 225 J

Read More: NCERT Solutions for Class 9 Science Chapter 4

NCERT Solutions Class 9 Science Chapter 10 Exercise 10.4

1. What is power?

Solution: Power is defined as the rate of doing work or the rate of transfer of energy. If an agent does a work W in time t, then power is given by:NCERT Solutions for Class 9 Science - Chapter 11 Image 2P = W/T It is expressed in watt (W).

2. Define 1 watt of power.

Solution:

A body is claimed to possess power of one watt if it works at the speed of 1 joule in 1 s. That is, One W = 1 J/1 S

3. A lamp consumes 1000 J of electrical energy in 10 s. What is its power?

Solution:

Power = Work/Time P = W/T Time = 10 s Work done = Energy consumed by the lamp = 1000 J Power = 1000/10 = 100 Js -1 =100 W Hence, the power of the lamp is 100 W

4. Define average power.

Solution: Average power is defined as the ratio of total work done by the body to the total time taken by the body.NCERT Solutions for Class 9 Science - Chapter 11 Image 3

Read MoreNCERT Solutions For Class 9 Science Chapter 5

NCERT Solutions Class 9 Science Chapter 10 Exercise 10.5

1. Look at the activities listed below. Reason out whether or not work is done in the light of your understanding of the term ‘work’.

(a) Suma is swimming in a pond.

(b)A donkey is carrying a load on its back.

(c) A windmill is lifting water from a well.

(d) A green plant is carrying out photosynthesis.

(e) An engine is pulling a train.

(f) Food grains are getting dried in the sun.

(g) A sailboat is moving due to wind energy.

Solution:

When both of the following two requirements are met, the work is completed:
(i) The body is subject to a force.
(ii) The body is moved by exerting force in the force's direction or the opposite direction.
(a) Suma uses force to push the water backward when swimming. As a result of the water's forward reaction, Suma swims in that direction. Here there is a displacement due to the force. Thus, Seema completes the task while swimming.
(b) The donkey must exert force upwards when it is carrying a load. Nonetheless, the load is being displaced forward. There is no labor done because displacement is perpendicular to force.
(c) A windmill raises water by defying gravity. Water is raised by the windmill by exerting force upward, which causes the water to move in the same upward direction. Thus, the windmill works to raise the water level in the well.
(d) When a green plant is performing photosynthesis, no force is needed. The plant moves without using any force. since neither force nor displacement exists. So, nothing is accomplished.
(e) An engine exerting force forward is what happens when it pulls a train. It is therefore travelling ahead. given that the direction of displacement and force is the same. Thus, the engine does the labor. (f) Food grains dry in the sun without the use of force, and they remain still during the process. since neither force nor displacement exists. So, nothing is accomplished.
(g) A sailboat exerts force forward when it moves as a result of wind energy. It is therefore travelling ahead. given that the direction of displacement and force is the same. So, the task is completed.
Read More: NCERT Solutions For Class 9 Science Chapter 6

2. An object thrown at a certain angle to the ground moves in a curved path and falls back to the ground. The initial and the final points of the path of the object lie on the same horizontal line. What is the work done by the force of gravity on the object?

Solution:

Work done by the force of gravity on an object depends solely on vertical displacement. Vertical displacement is given by the distinction in the initial and final positions/heights of the object which is zero. Work done by gravity is given by the expression, W = m × g × h Where, h= Vertical displacement = 0 W = m g × 0 = 0 J Hence, the work done by the gravity on the given object is zero joule.

3. A battery lights a bulb. Describe the energy changes involved in the process.

Solution:

The energy in a battery is converted into voltage when a light is connected to it. The voltage is converted into heat and light energy by the lightbulb once it has received it. As a result, the energy transformation in the given scenario can be represented as follows: Chemical Energy → Electrical Energy → Light Energy + Heat Energy.

4. Certain force acting on a 20 kg mass changes its velocity from 5 m s -1 to 2 m s -1 . Calculate the work done by the force.

Solution:

Given Initial velocity u = 5 m/s Mass of the body = 20kg Final velocity v = 2 m/s The initial kinetic energy E = (1/2) mu = (1/2) × 20 × (5) = 10 × 25 = 250 J Final kinetic energy E = (1/2) mv = (1/2) × 20 × (2) = 10 × 4 = 40 J Therefore, Work done = Change in kinetic energy Work done = E – E Work done = 40 J – 250 J Work done = -210 J

5. A mass of 10 kg is at point A on a table. It is moved to a point B. If the line joining A and B is horizontal, what is the work done on the object by the gravitational force? Explain your answer.

Solution:

Work done by gravity depends solely on the vertical displacement of the body. It doesn’t rely on the trail of the body. Therefore, work done by gravity is given by the expression, W= m g h Where, Vertical displacement, h = 0 ∴ W= m × g × zero = 0 Therefore the work done on the object by gravity is zero.

6. The potential energy of a freely falling object decreases progressively. Does this violate the law of conservation of energy? Why?

Solution:

The energy conservation law is not broken by this procedure. This is because the body gradually transforms its potential energy into kinetic energy when it descends from a height. The body's kinetic energy increases in proportion to a decrease in potential energy. The body's whole mechanical energy is conserved during the process. As a result, the law of energy conservation remains intact.

7. What are the various energy transformations that occur when you are riding a bicycle?

Solution:

The muscle energy of a bicycle rider is converted into mechanical energy and heat during the ride. The bicycle is propelled by kinetic energy, while our bodies are heated by thermal energy. Muscular energy → mechanical energy + heat

8. Does the transfer of energy take place when you push a huge rock with all your might and fail to move it? Where is the energy you spend going?

Solution:

There is no muscle energy transfer to the stationary rock when we push a large boulder. Additionally, since muscular energy is converted into heat energy, which raises our body's temperature, there is no energy loss.

9. A certain household has consumed 250 units of energy during a month. How much energy is this in joules?

Solution:

1 unit of energy = 1kWh Given Energy (E) = 250 units 1 unit = 1 kWh 1 kWh = 3.6 x 10 J Therefore, 250 units of energy = 250 × 3.6 × 10 = 9 × 10 J.

10. An object of mass 40 kg is raised to a height of 5 m above the ground. What is its potential energy? If the object is allowed to fall, find its kinetic energy when it is halfway down.

Solution:

Given Mass (m) = 40 kg Acceleration due to gravity (g)= 10m/s² Height (h)= 5m Potential energy= m × g× h P.E= 40 × 10 × 5 = 2000J Potential energy = 2000J ( 2000 joules) At a height of 5 meters, the object has a potential energy of 2000 J. When this object is allowed to fall and it is halfway down, its height above the ground will be half of 5 m= 5/2= 2.5m. P.E at Halfway down= m× g×h P.E= 40× 10 × 2.5= 1000J [h= 2.5 m] Potential Energy halfway down= 1000 joules. According to the law of conservation of energy: Total potential energy potential energy halfway down kinetic energy halfway down 2000 = 1000 + K.E halfway down K.E at halfway down= 2000- 1000= 1000 J Kinetic energy at halfway down 1000 joules.

Read more: NCERT Solutions for Class 9 Science Chapter 12

11. What is the work done by the force of gravity on a satellite moving around the earth? Justify your answer.

Solution:

When both of the following two requirements are met, work is considered finished: (i) The body is subject to a force. (ii) The body is moved by exerting force in the force's direction or the opposite direction. The work done is 0 if the force's direction is perpendicular to the displacement. The force of gravity acting on a satellite throughout its orbit around the Earth is perpendicular to the spacecraft's displacement. As a result, Earth has done zero work on the satellite.

12. Can there be displacement of an object in the absence of any force acting on it? Think. Discuss this question with your friends and teacher

Solution:

In the absence of any force acting on an object, displacement is indeed possible. An object accelerates when subjected to a single force. An object is subject to a force if it accelerates. Let's say that an object is traveling at a constant speed. There is no net force acting on it. However, the thing moves, and with it, a displacement. Consequently, a displacement is possible in the absence of a force.

13. A person holds a bundle of hay over his head for 30 minutes and gets tired. Has he done some work or not? Justify your answer.

Solution:

When the two requirements are met, the work is finished. (i) The body is subject to a force. (ii) The body is moved by exerting force in the force's direction or the opposite direction. There isn't any movement in a hay bundle when someone holds it above their head. The bundle is being affected by the force of gravity, but the individual is not exerting any effort on it. Consequently, the person's work on the bundle is zero in the absence of force.

14. An electric heater is rated 1500 W. How much energy does it use in 10 hours?

Solution:

Given, Power of the heater = 1500 W = 1.5 kW Time taken = 10 hours Energy consumed by an electric heater can be obtained with the help of the expression, Power = Energy consumed / Time taken Hence, Energy consumed = Power x Time taken Energy consumed = 1.5 x 10 Energy consumed = 15 kWh Therefore, the energy consumed by the heater in 10 hours is 15 kWh.

15. Illustrate the law of conservation of energy by discussing the energy changes that occur when we draw a pendulum bob to one side and allow it to oscillate. Why does the bob eventually come to rest? What happens to its energy eventually? Is it a violation of the law of conservation of energy?

Solution:

Consider the case of an oscillation pendulum.NCERT Solutions for Class 9 Science - Chapter 11 Image 4An apparatus rises via a height h on top of the mean level P when it moves from its mean position P to either of its extreme locations A or B. At this point, the bob's K.E. completely transforms into P.E. When this happens, the K.E. drops to zero and the bob just has P.E. As it advances in the direction of goal P, its P.E. steadily drops. As a result, the K.E. will rise. The bob's P.E. drops to zero when it achieves goal P, and it likewise just has K.E. For as long as the device oscillates, this technique is perpetual. The bob does not continuously oscillate. Because of the air resistance preventing it from moving, it comes to rest. To overcome this friction, the device occasionally stops and loses its K.E. The energy wasted by the device to overcome friction is recovered by its surroundings, therefore the rule of conservation of energy is not violated. As a result, the apparatus's total energy as well as the surrounding system is maintained.

16. An object of mass, m is moving with a constant velocity, v. How much work should be done on the object to bring the object to rest?

Solution:

The kinetic energy of an object of mass m, moving with a velocity, v, is given by the expression, K.E = 1/2 mv To bring it to rest, its velocity has to be reduced to zero, and to accomplish that, the kinetic energy has to be drained off and sent somewhere else. An external force has to absorb energy from the object, i.e. do negative work on it, equal to its kinetic energy, or – 1/2 mv .

17. Calculate the work required to be done to stop a car of 1500 kg moving at a velocity of 60 km/h.

Solution:

Given data: The mass of the body = 1500kg Velocity v = 60km/hrNCERT Solutions for Class 9 Science - Chapter 11 Image 7The work required to stop the moving car = change in kinetic energy.

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Solving Work and Energy Class 9 Questions and Answers

When you read work and energy class 9 questions and answers, the first big idea is what "work" really means. In science, work is not just doing homework or thinking hard. It only counts as work if you use a push or pull to move something.

  • Rule 1: You must use a force (a push or a pull).

  • Rule 2: The thing you push must move from its spot.

If you push a big tree and it stays still, you did zero work. We find the amount of work by multiplying the push by the distance the object moved. The formula is W = F \times . Here,W is work, F is the push, and s is the distance. If you push a toy car and it moves forward, you did positive work. If something tries to stop the car, like grass rubbing against the wheels, that is negative work.

Using Work and Energy Class 9 Questions and Answers PDF

Looking at a work and energy class 9 questions and answers pdf helps you see how energy changes. Energy does not just vanish and it is not made from nothing. It just moves from one type to another type. This is a very important rule in science.

Two Main Types of Energy:

  • Moving Energy (Kinetic): This is the energy things have because they are moving. A fast ball has a lot of this. The formula is E_k = \frac{1}{2} mv^2.

  • Stored Energy (Potential): This is energy saved up because of where something is. A rock high on a hill has this. The formula is E_p = mgh.

Think of a ball on a slide. At the top, it has stored energy. When it starts to slide down, that stored energy turns into moving energy. By the time it hits the bottom, it is going very fast!

Work and Energy Class 9 Questions and Answers Extra

Doing work and energy class 9 questions and answers extra helps you learn how to solve math problems. One tricky thing to know is that if you carry a box and walk flat on the floor, gravity does no work. This is because you are moving sideways but gravity pulls down.

Simple Rules to Remember:

  • Always use kilograms for weight.

  • Always use meters for how far something moved.

  • A "horsepower" is another way to talk about power; it is 746 Watts.

  • If things don't move, work is always zero.

When you do these problems, you will see that if a car goes twice as fast, it needs four times the energy to stop. This is because the speed is multiplied by itself in the energy formula. Knowing this helps you stay safe and understand how cars work.

Check Out: Class 9th Revision Books

Essential Work and Energy Class 9 Questions and Answers NCERT

The work and energy class 9 questions and answers NCERT focus on the core curriculum. These are the "must-know" problems for every student. They cover everything from the definition of 1 Joule to the Law of Conservation of Energy.

Sl. No

Topic

Key Formula

1

Work

W = Fs cos θ

2

Kinetic Energy

E_k = 1/2 mv^2

3

Potential Energy

E_p = mgh

4

Power

P = W/t

Common Textbook Problems

  1. Calculating Kinetic Energy: If a ball's mass is doubled, how does its energy change?

  2. Defining Power: You'll learn that power is the rate of doing work.

  3. Unit Conversions: Changing Kilowatt-hours (kWh) into Joules is a vital skill.

Work and Energy Class 9 Questions and Answers Exercise

The work and energy class 9 questions and answers exercise brings everything together. You might need to find how much power a light bulb uses or how much work a horse does. You just have to follow the steps and use the right numbers.

Why is this helpful for you?

  • It tells you how toys and cars move.

  • It helps you understand why we pay for electricity.

  • It shows you how to use math to solve real-life things.

  • It makes science feel like a fun puzzle.

At the end of the day, work and energy are like best friends. You need energy to do work. When you do work on something, you give it energy. It is a big loop that never ends!

Benefit of Digital Notes

You can search for specific terms quickly. Instead of flipping pages, you just type "Power" and find every related question. It saves time and keeps your study desk organized.

Check OutCBSE Class 9 Question Banks

Work and Energy Question and Answer FAQs

What is the unit for work?

The unit is the Joule. It is named after a famous scientist. We use it to measure both work and energy.

Can work be zero?

Yes! If you push as hard as you can but the object does not move, the work is zero. Also, if you carry something flat across a room, gravity does zero work.

What is the Law of Conservation of Energy?

This rule says energy can't be made or broken. It only changes its "look." For example, heat can turn into movement.

How do we measure power at home?

We use kilowatt-hours (kWh). This is what you see on the electric meter outside your house. It tells you how much energy you used.

Does a heavier object have more energy?

Yes. If two things move at the same speed, the heavier one has more moving energy. If they are at the same height, the heavier one has more stored energy.

What is 1 kilowatt-hour (kWh)? 

It's a unit of energy used for commercial purposes. 1 kWh = 3.6 × 10^6 Joules.

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NCERT Solutions for Class 9 Science Chapter 10 Work and Energy