Mole Concept Questions with Answers for JEE Exam

Mole concept is one of the most important topics in chemistry. It helps students understand how to measure and calculate substances at the atomic level. This topic is a basic part of physical chemistry and is used in solving many problems in exams.

The JEE exam has two parts: JEE Main and JEE Advanced. Chemistry is a key subject in both exams, and the mole concept is an important part of it. In JEE Main, one or two direct questions on the mole concept are asked almost every year. In JEE Advanced, questions are generally more tricky and need a deeper understanding of stoichiometry and related concepts.

Because the mole concept is important for many chapters, practising the mole concept JEE Mains questions is very helpful. Keep reading to check the mole concept questions with answers for mains and advanced that will help in your exam preparation.

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Mole Concept JEE Questions with Answers Overview

The mole concept helps connect tiny particles like atoms and molecules to real, measurable quantities such as mass and volume. It allows applicants to calculate the number of particles, balance chemical equations, and find limiting reagents.

Mole concept JEE Mains questions are generally asked as numerical or multiple-choice, to test applicants' speed and accuracy. These questions are generally based on concepts like Avogadro’s number, molar mass, empirical formulas, and equivalents.

Mole concept JEE Advanced questions are more challenging as compared to Mains. They generally need deeper thinking and more than one step to solve. Practising the important mole concept JEE Mains questions along with PYQs helps students improve calculation skills and apply formulas in different situations. Let’s now check some key mole concept JEE Mains questions.

Check Out: JEE Previous Year Papers

Mole Concept JEE Mains Questions With Answers

Here are some important mole concept JEE Mains questions with answers taken from previous years’ papers. Practising them will help you build speed and accuracy:

1. 20 mL of sodium iodide solution gave 4.74 g of silver iodide when treated with an excess of silver nitrate solution. The molarity of the sodium iodide solution is ______ M. (Nearest integer value)
(Given: Na = 23, I = 127, Ag = 108, N = 14, O = 16 g mol⁻¹)

2. The amount of calcium oxide produced on heating 150 kg of limestone (75% pure) is ________ kg. (Nearest integer)
(Given: Molar mass (in g mol⁻¹) of Ca = 40, O = 16, C = 12)

3. Mass of magnesium required to produce 220 mL of hydrogen gas at STP on reaction with an excess of dil. HCl is ______.
(Given: Molar mass of Mg = 24 g mol⁻¹)

(a) 235.7 g (b) 0.24 mg (c) 236 mg (d) 2.444 g

4. Among 10–9 g (each) of the following elements, which one will have the highest number of atoms?
Elements: Pb, Po, Pr and Pt

(a) Po (b) Pr (c) Pb (d) Pt

5. 0.1 mol of the following given antiviral compound (P) will weigh _______ × 10–1 g [02 April, 2025 (Shift-I)]

(Given: molar mass in g mol–1 H: 1, C: 12, N: 14, O: 16, F: 19, I: 127)

6. On complete combustion, 1.0 g of an organic compound (X) gave 1.46 g of CO₂ and 0.567 g of H₂O. The empirical formula mass of compound (X) is _________ g.
(Given molar mass in g mol⁻¹: C = 12, H = 1, O = 16)
(a) 30 (b) 45 (c) 60 (d) 15

7. 0.01 mole of an organic compound (X) containing 10% hydrogen, on complete combustion, produced 0.9 g H₂O. The molar mass of (X) is ________ g mol⁻¹.

8. 2.8 × 10⁻³ mol of CO₂ is left after removing 10²¹ molecules from its ‘x’ mg sample. The mass of CO₂ taken initially is
(Given: N_A = 6.02 × 10²³ mol⁻¹)

(a) 48.2 mg (b) 98.3 mg (c) 150.4 mg (d) 196.2 mg

9. A 0.05 cm thick coating of silver is deposited on a plate of 0.05 m² area. The number of silver atoms deposited on plate are __________ × 10²³.
(At mass Ag = 108, d = 7.9 g cm⁻³)

19. The number of molecules and moles in 2.8375 litres of O₂ at STP are, respectively:
[10 April, 2023 (Shift-I)]
(a) 7.527 × 10²² and 0.250 mol
(b) 1.505 × 10²³ and 0.250 mol
(c) 7.527 × 10²³ and 0.125 mol
(d) 7.527 × 10²² and 0.125 mol

Answers:

1. 63

2. (c)

3. (b)

4. 372

5. (a)

6. (100)

7. (d)

8. (11)

9. (d)

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Mole Concept JEE Advanced Questions With Answers

Check some important mole concept JEE Advanced questions from past exams here. Solving them helps you develop a deeper understanding and problem-solving skills for the upcoming advanced level:

1. An aqueous solution of 6.3 g oxalic acid dihydrate is made up to 250 mL. The volume of 0.1 N NaOH required to completely neutralise 10 mL of this solution is (IIT JEE 2001)
(a) 40 mL (b) 20 mL (c) 10 mL (d) 4 mL

2. The normality of 0.3M phosphorous acid (H₃PO₃) is (IIT JEE 1999)
(a) 0.1 (b) 0.9 (c) 0.3 (d) 0.6

3. In which mode of expression does the concentration of a solution remain independent of temperature? (IIT JEE 1998)
(a) Molarity (b) Normality (c) Formality (d) Molality

4. The volume strength of 1.5 N H₂O₂ is (IIT JEE 1990)
(a) 4.8 (b) 8.4 (c) 3.0 (d) 8.0

5. A molal solution is one that contains one mole of solute in (IIT JEE 1986)
(a) 1000 g of solvent (b) 1.0 L of solvent (c) 1.0 L of solution (d) 22.4 L of solution

6. If 0.50 mole of BaCl₂ is mixed with 0.20 mole of Na₃PO₄, the maximum number of moles of Ba₃(PO₄)₂ that can be formed is (IIT JEE 1981)
(a) 0.70 (b) 0.50 (c) 0.20 (d) 0.10

7. The total number of electrons in one molecule of carbon dioxide is (IIT JEE 1979)
(a) 22 (b) 44 (c) 68 (d) 88

8. To form a complete monolayer of acetic acid on 1 g of charcoal, 100 mL of 0.5 M acetic acid was used. Some of the acetic acid remained unadsorbed. To neutralise the unadsorbed acetic acid, 40 mL of 1 M NaOH solution was required. If each molecule of acetic acid occupies P × 10⁻²³ m² surface area on charcoal, the value of P is ___________.
[Use given data: Surface area of charcoal = 1.5 × 10² m² g⁻¹; Avogadro’s number (N_A) = 6.0 × 10²³ mol⁻¹]
C-15.73 W-60.25 UA-24.03 (JEE Adv. 2024)

9. Aluminium reacts with sulphuric acid to form aluminium sulphate and hydrogen. What is the volume of hydrogen gas in litres (L) produced at 300 K and 1.0 atm pressure, when 5.4 g of aluminium and 50.0 mL of 5.0 M sulphuric acid are combined for the reaction?
(Use molar mass of aluminium as 27.0 g mol⁻¹, R = 0.082 atm L mol⁻¹ K⁻¹)
C-18.21 W-64.19 UA-17.6 PC-0 (JEE Adv. 2020)

10. The mole fraction of urea in an aqueous urea solution containing 900 g of water is 0.05. If the density of the solution is 1.2 g cm⁻³, the molarity of the urea solution is ___.
(Given data: Molar masses of urea and water are 60 g mol⁻¹ and 18 g mol⁻¹, respectively.)
C-17.05 W-70.35 UA-12.61 (JEE Adv. 2019)

Answers:

1. (a)

2. (d)

3. (d)

4. (b)

5. (a)

6. (d)

7. (a)

8. (2500)

9. (6.15)

10. (2.98 or 2.99)

Read More: JEE Main Chemistry Syllabus for 2026 Exam

Mole Concept JEE Mains Questions PDF Download

The mole concept JEE Mains questions PDF download link is given here. It serves as a study resource to boost your JEE exam preparation. This PDF includes important mole concept PYQ JEE Mains as well as JEE Advanced questions taken from past years. It also gives different types of questions, such as numerical problems, subjective questions, and MCQs, all with detailed answers and step-by-step explanations.

Along with questions, this mole concept all formulas PDF JEE helps students to revise quickly. It covers important topics from the mole concept class 11 questions JEE syllabus to help you strengthen the basics. That's why, using the Mole Concept JEE Mains Questions PDF Download link, you can improve your problem-solving speed for both JEE Main and Advanced exams.

Mole Concept JEE Mains Questions PDF Download Link

JEE Chemistry Preparation Books by PW

For effective preparation for JEE Chemistry, choosing the right study material is very important. JEE Books by PW for chemistry preparation are curated to help you build a strong foundation in concepts while practising different types of questions.

These books cover key topics such as the mole concept class 11 questions JEE, along with others, for both mains and advanced. With easy-to-understand explanations, solved examples, and previous years’ questions, these PW JEE study materials make learning effective and easy for the upcoming JEE Main and JEE Advanced.

Mole Concept Questions with Answers for JEE Exam FAQs

Q.1. Is the mole concept an important topic for the JEE exams?

Ans. Yes, the mole concept is one of the most important topics for both the JEE Main and JEE Advanced exams. It forms the base of physical chemistry and is used to solve many types of numerical problems related to reactions and calculations.

Q.2. How many mole concept JEE Mains questions are asked in the exam?

Ans. Generally, one or two mole concept JEE Mains questions are asked every year. These are mostly formula-based or numerical questions that test your understanding of basic concepts.

Q.3. Does the mole concept JEE Advanced question-solving help with other chemistry topics as well?

Ans. Yes, practising the mole concept JEE Advanced questions helps with many other chapters too, as its concepts are also used in topics like chemical equilibrium, thermodynamics, redox reactions, and stoichiometry.

Q.4. Where can I access the mole concept JEE Mains questions PDF download link?

Ans. You can find the mole concept JEE Mains questions PDF download link above in this article.

Q.5. When should I utilise the mole concept JEE Advanced questions PDF?

Ans. Use the mole concept JEE Advanced questions PDF after finishing the chapter once from your NCERT book. It is best to solve it while revising or before mock tests to improve your problem-solving speed and accuracy.